3(n-7)+n=12-2(3n+7)

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Solution for 3(n-7)+n=12-2(3n+7) equation: 



3(n-7)+n=12-2(3n+7)

We move all terms to the left:

3(n-7)+n-(12-2(3n+7))=0

We add all the numbers together, and all the variables

n+3(n-7)-(12-2(3n+7))=0

We multiply parentheses

n+3n-(12-2(3n+7))-21=0



We calculate terms in parentheses: -(12-2(3n+7)), so:

12-2(3n+7)

determiningTheFunctionDomain
-2(3n+7)+12

We multiply parentheses

-6n-14+12

We add all the numbers together, and all the variables

-6n-2

Back to the equation:

-(-6n-2)



We add all the numbers together, and all the variables

4n-(-6n-2)-21=0

We get rid of parentheses

4n+6n+2-21=0

We add all the numbers together, and all the variables

10n-19=0

We move all terms containing n to the left, all other terms to the right

10n=19

n=19/10

n=1+9/10

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