3(n-4)=2n+7(n+6)

Solution for 3(n-4)=2n+7(n+6) equation:

3(n-4)=2n+7(n+6)

We move all terms to the left:

3(n-4)-(2n+7(n+6))=0

We multiply parentheses

3n-(2n+7(n+6))-12=0


We calculate terms in parentheses: -(2n+7(n+6)), so:

2n+7(n+6)

We multiply parentheses

2n+7n+42

We add all the numbers together, and all the variables

9n+42

Back to the equation:

-(9n+42)


We get rid of parentheses

3n-9n-42-12=0

We add all the numbers together, and all the variables

-6n-54=0

We move all terms containing n to the left, all other terms to the right

-6n=54

n=54/-6

n=-9