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0.3x-3/5x+1.6=1.555
We move all terms to the left:
0.3x-3/5x+1.6-(1.555)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
0.3x-3/5x+0.045=0
We multiply all the terms by the denominator
(0.3x)*5x+(0.045)*5x-3=0
We add all the numbers together, and all the variables
(+0.3x)*5x+(0.045)*5x-3=0
We multiply parentheses
0x^2+0.225x-3=0
We add all the numbers together, and all the variables
x^2+0.225x-3=0
a = 1; b = 0.225; c = -3;
Δ = b2-4ac
Δ = 0.2252-4·1·(-3)
Δ = 12.050625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.225)-\sqrt{12.050625}}{2*1}=\frac{-0.225-\sqrt{12.050625}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.225)+\sqrt{12.050625}}{2*1}=\frac{-0.225+\sqrt{12.050625}}{2} $
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