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2(6z-2)=-2(-2z+2)
We move all terms to the left:
2(6z-2)-(-2(-2z+2))=0
We multiply parentheses
12z-(-2(-2z+2))-4=0
We calculate terms in parentheses: -(-2(-2z+2)), so:We get rid of parentheses
-2(-2z+2)
We multiply parentheses
4z-4
Back to the equation:
-(4z-4)
12z-4z+4-4=0
We add all the numbers together, and all the variables
8z=0
z=0/8
z=0
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