3(n-2)=3(1+n)=9

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Solution for 3(n-2)=3(1+n)=9 equation: 



3(n-2)=3(1+n)=9

We move all terms to the left:

3(n-2)-(3(1+n))=0

We add all the numbers together, and all the variables

3(n-2)-(3(n+1))=0

We multiply parentheses

3n-(3(n+1))-6=0



We calculate terms in parentheses: -(3(n+1)), so:

3(n+1)

We multiply parentheses

3n+3

Back to the equation:

-(3n+3)



We get rid of parentheses

3n-3n-3-6=0

We add all the numbers together, and all the variables

-9!=0

There is no solution for this equation

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