1/3(9x+33)=3x+1

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Solution for 1/3(9x+33)=3x+1 equation: 



1/3(9x+33)=3x+1

We move all terms to the left:

1/3(9x+33)-(3x+1)=0



Domain of the equation: 3(9x+33)!=0

x∈R



We get rid of parentheses

1/3(9x+33)-3x-1=0

We multiply all the terms by the denominator


-3x*3(9x+33)-1*3(9x+33)+1=0

Wy multiply elements

-9x^2(9-3x(9+1=0

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