3(n+4)=3(n-5)

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Solution for 3(n+4)=3(n-5) equation: 



3(n+4)=3(n-5)

We move all terms to the left:

3(n+4)-(3(n-5))=0

We multiply parentheses

3n-(3(n-5))+12=0



We calculate terms in parentheses: -(3(n-5)), so:

3(n-5)

We multiply parentheses

3n-15

Back to the equation:

-(3n-15)



We get rid of parentheses

3n-3n+15+12=0

We add all the numbers together, and all the variables

27!=0

There is no solution for this equation

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