5(2y-3)=40y

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Solution for 5(2y-3)=40y equation: 



5(2y-3)=40y

We move all terms to the left:

5(2y-3)-(40y)=0

We add all the numbers together, and all the variables

-40y+5(2y-3)=0

We multiply parentheses

-40y+10y-15=0

We add all the numbers together, and all the variables

-30y-15=0

We move all terms containing y to the left, all other terms to the right

-30y=15

y=15/-30

y=-1/2

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