3(n+4)=1/2(n+4

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Solution for 3(n+4)=1/2(n+4 equation: 



3(n+4)=1/2(n+4

We move all terms to the left:

3(n+4)-(1/2(n+4)=0



Domain of the equation: 2(n+4)!=0

n∈R



We multiply parentheses

3n-(1/2(n+4)+12=0

We multiply all the terms by the denominator


3n*2(n+4)+12-(1=0

We add all the numbers together, and all the variables

3n*2(n+4)=0

Wy multiply elements

6n^2(n=0

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