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4(2y-3)=3+8y-15
We move all terms to the left:
4(2y-3)-(3+8y-15)=0
We add all the numbers together, and all the variables
4(2y-3)-(8y-12)=0
We multiply parentheses
8y-(8y-12)-12=0
We get rid of parentheses
8y-8y+12-12=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0
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