3(n+4)-3(n+2)=8

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Solution for 3(n+4)-3(n+2)=8 equation: 


Simplifying
3(n + 4) + -3(n + 2) = 8

Reorder the terms:
3(4 + n) + -3(n + 2) = 8
(4 * 3 + n * 3) + -3(n + 2) = 8
(12 + 3n) + -3(n + 2) = 8

Reorder the terms:
12 + 3n + -3(2 + n) = 8
12 + 3n + (2 * -3 + n * -3) = 8
12 + 3n + (-6 + -3n) = 8

Reorder the terms:
12 + -6 + 3n + -3n = 8

Combine like terms: 12 + -6 = 6
6 + 3n + -3n = 8

Combine like terms: 3n + -3n = 0
6 + 0 = 8
6 = 8

Solving
6 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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