-5(z-1)+(3z+1)=3(n-11)

Solution for -5(z-1)+(3z+1)=3(n-11) equation:

Simplifying
-5(z + -1) + (3z + 1) = 3(n + -11)

Reorder the terms:
-5(-1 + z) + (3z + 1) = 3(n + -11)
(-1 * -5 + z * -5) + (3z + 1) = 3(n + -11)
(5 + -5z) + (3z + 1) = 3(n + -11)

Reorder the terms:
5 + -5z + (1 + 3z) = 3(n + -11)

Remove parenthesis around (1 + 3z)
5 + -5z + 1 + 3z = 3(n + -11)

Reorder the terms:
5 + 1 + -5z + 3z = 3(n + -11)

Combine like terms: 5 + 1 = 6
6 + -5z + 3z = 3(n + -11)

Combine like terms: -5z + 3z = -2z
6 + -2z = 3(n + -11)

Reorder the terms:
6 + -2z = 3(-11 + n)
6 + -2z = (-11 * 3 + n * 3)
6 + -2z = (-33 + 3n)

Solving
6 + -2z = -33 + 3n

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -2z = -33 + -6 + 3n

Combine like terms: 6 + -6 = 0
0 + -2z = -33 + -6 + 3n
-2z = -33 + -6 + 3n

Combine like terms: -33 + -6 = -39
-2z = -39 + 3n

Divide each side by '-2'.
z = 19.5 + -1.5n

Simplifying
z = 19.5 + -1.5n