3(n+4)+8=2+n

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Solution for 3(n+4)+8=2+n equation: 



3(n+4)+8=2+n

We move all terms to the left:

3(n+4)+8-(2+n)=0

We add all the numbers together, and all the variables

3(n+4)-(n+2)+8=0

We multiply parentheses

3n-(n+2)+12+8=0

We get rid of parentheses

3n-n-2+12+8=0

We add all the numbers together, and all the variables

2n+18=0

We move all terms containing n to the left, all other terms to the right

2n=-18

n=-18/2

n=-9

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