3(n+1)=6(n-2)

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Solution for 3(n+1)=6(n-2) equation: 



3(n+1)=6(n-2)

We move all terms to the left:

3(n+1)-(6(n-2))=0

We multiply parentheses

3n-(6(n-2))+3=0



We calculate terms in parentheses: -(6(n-2)), so:

6(n-2)

We multiply parentheses

6n-12

Back to the equation:

-(6n-12)



We get rid of parentheses

3n-6n+12+3=0

We add all the numbers together, and all the variables

-3n+15=0

We move all terms containing n to the left, all other terms to the right

-3n=-15

n=-15/-3

n=+5

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