8(c+3)=4(c-5)

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Solution for 8(c+3)=4(c-5) equation: 



8(c+3)=4(c-5)

We move all terms to the left:

8(c+3)-(4(c-5))=0

We multiply parentheses

8c-(4(c-5))+24=0



We calculate terms in parentheses: -(4(c-5)), so:

4(c-5)

We multiply parentheses

4c-20

Back to the equation:

-(4c-20)



We get rid of parentheses

8c-4c+20+24=0

We add all the numbers together, and all the variables

4c+44=0

We move all terms containing c to the left, all other terms to the right

4c=-44

c=-44/4

c=-11

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