3(n+1)=4+2n

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Solution for 3(n+1)=4+2n equation: 



3(n+1)=4+2n

We move all terms to the left:

3(n+1)-(4+2n)=0

We add all the numbers together, and all the variables

3(n+1)-(2n+4)=0

We multiply parentheses

3n-(2n+4)+3=0

We get rid of parentheses

3n-2n-4+3=0

We add all the numbers together, and all the variables

n-1=0

We move all terms containing n to the left, all other terms to the right

n=1

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