-7(v+1)=3v-3+2(3v+1)

Solution for -7(v+1)=3v-3+2(3v+1) equation:

-7(v+1)=3v-3+2(3v+1)

We move all terms to the left:

-7(v+1)-(3v-3+2(3v+1))=0

We multiply parentheses

-7v-(3v-3+2(3v+1))-7=0


We calculate terms in parentheses: -(3v-3+2(3v+1)), so:

3v-3+2(3v+1)

determiningTheFunctionDomain
3v+2(3v+1)-3

We multiply parentheses

3v+6v+2-3

We add all the numbers together, and all the variables

9v-1

Back to the equation:

-(9v-1)


We get rid of parentheses

-7v-9v+1-7=0

We add all the numbers together, and all the variables

-16v-6=0

We move all terms containing v to the left, all other terms to the right

-16v=6

v=6/-16

v=-3/8