3(m-9)-m=9(-11-2m)-10m

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Solution for 3(m-9)-m=9(-11-2m)-10m equation: 



3(m-9)-m=9(-11-2m)-10m

We move all terms to the left:

3(m-9)-m-(9(-11-2m)-10m)=0

We add all the numbers together, and all the variables

3(m-9)-m-(9(-2m-11)-10m)=0

We add all the numbers together, and all the variables

-1m+3(m-9)-(9(-2m-11)-10m)=0

We multiply parentheses

-1m+3m-(9(-2m-11)-10m)-27=0



We calculate terms in parentheses: -(9(-2m-11)-10m), so:

9(-2m-11)-10m

We add all the numbers together, and all the variables

-10m+9(-2m-11)

We multiply parentheses

-10m-18m-99

We add all the numbers together, and all the variables

-28m-99

Back to the equation:

-(-28m-99)



We add all the numbers together, and all the variables

2m-(-28m-99)-27=0

We get rid of parentheses

2m+28m+99-27=0

We add all the numbers together, and all the variables

30m+72=0

We move all terms containing m to the left, all other terms to the right

30m=-72

m=-72/30

m=-2+2/5

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