44=2(5+2n)+2(n-4)

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Solution for 44=2(5+2n)+2(n-4) equation: 



44=2(5+2n)+2(n-4)

We move all terms to the left:

44-(2(5+2n)+2(n-4))=0

We add all the numbers together, and all the variables

-(2(2n+5)+2(n-4))+44=0



We calculate terms in parentheses: -(2(2n+5)+2(n-4)), so:

2(2n+5)+2(n-4)

We multiply parentheses

4n+2n+10-8

We add all the numbers together, and all the variables

6n+2

Back to the equation:

-(6n+2)



We get rid of parentheses

-6n-2+44=0

We add all the numbers together, and all the variables

-6n+42=0

We move all terms containing n to the left, all other terms to the right

-6n=-42

n=-42/-6

n=+7

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