3(m-5)=7(2m+1)

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Solution for 3(m-5)=7(2m+1) equation: 



3(m-5)=7(2m+1)

We move all terms to the left:

3(m-5)-(7(2m+1))=0

We multiply parentheses

3m-(7(2m+1))-15=0



We calculate terms in parentheses: -(7(2m+1)), so:

7(2m+1)

We multiply parentheses

14m+7

Back to the equation:

-(14m+7)



We get rid of parentheses

3m-14m-7-15=0

We add all the numbers together, and all the variables

-11m-22=0

We move all terms containing m to the left, all other terms to the right

-11m=22

m=22/-11

m=-2

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