3(m+5)-2m=3-(4m-2)

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Solution for 3(m+5)-2m=3-(4m-2) equation: 



3(m+5)-2m=3-(4m-2)

We move all terms to the left:

3(m+5)-2m-(3-(4m-2))=0

We add all the numbers together, and all the variables

-2m+3(m+5)-(3-(4m-2))=0

We multiply parentheses

-2m+3m-(3-(4m-2))+15=0



We calculate terms in parentheses: -(3-(4m-2)), so:

3-(4m-2)

determiningTheFunctionDomain
-(4m-2)+3

We get rid of parentheses

-4m+2+3

We add all the numbers together, and all the variables

-4m+5

Back to the equation:

-(-4m+5)



We add all the numbers together, and all the variables

m-(-4m+5)+15=0

We get rid of parentheses

m+4m-5+15=0

We add all the numbers together, and all the variables

5m+10=0

We move all terms containing m to the left, all other terms to the right

5m=-10

m=-10/5

m=-2

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