3/7=(a-2)/6

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Solution for 3/7=(a-2)/6 equation: 



3/7=(a-2)/6

We move all terms to the left:

3/7-((a-2)/6)=0

We calculate fractions


(-((a-2)*7)/()+()/()=0



We calculate terms in parentheses: +(-((a-2)*7)/()+()/(), so:

-((a-2)*7)/()+()/(

We add all the numbers together, and all the variables

-((a-2)*7)/()+1

We multiply all the terms by the denominator


-((a-2)*7)+1*()



We calculate terms in parentheses: -((a-2)*7), so:

(a-2)*7

We multiply parentheses

7a-14

Back to the equation:

-(7a-14)



We add all the numbers together, and all the variables

-(7a-14)

We get rid of parentheses

-7a+14

Back to the equation:

+(-7a+14)



We get rid of parentheses

-7a+14=0

We move all terms containing a to the left, all other terms to the right

-7a=-14

a=-14/-7

a=+2

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