3(m+2)=(12m+24)

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Solution for 3(m+2)=(12m+24) equation: 



3(m+2)=(12m+24)

We move all terms to the left:

3(m+2)-((12m+24))=0

We multiply parentheses

3m-((12m+24))+6=0



We calculate terms in parentheses: -((12m+24)), so:

(12m+24)

We get rid of parentheses

12m+24

Back to the equation:

-(12m+24)



We get rid of parentheses

3m-12m-24+6=0

We add all the numbers together, and all the variables

-9m-18=0

We move all terms containing m to the left, all other terms to the right

-9m=18

m=18/-9

m=-2

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