x2+64x-1280=0

Solution for x2+64x-1280=0 equation:

x2+64x-1280=0

We add all the numbers together, and all the variables

x^2+64x-1280=0

a = 1; b = 64; c = -1280;
Δ = b2-4ac
Δ = 642-4·1·(-1280)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-96}{2*1}=\frac{-160}{2}
=-80
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+96}{2*1}=\frac{32}{2}
=16
$