3(k-5)-(2k+3)=-7

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Solution for 3(k-5)-(2k+3)=-7 equation: 



3(k-5)-(2k+3)=-7

We move all terms to the left:

3(k-5)-(2k+3)-(-7)=0

We add all the numbers together, and all the variables

3(k-5)-(2k+3)+7=0

We multiply parentheses

3k-(2k+3)-15+7=0

We get rid of parentheses

3k-2k-3-15+7=0

We add all the numbers together, and all the variables

k-11=0

We move all terms containing k to the left, all other terms to the right

k=11

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