3(k-1)=2(k-1)

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Solution for 3(k-1)=2(k-1) equation: 



3(k-1)=2(k-1)

We move all terms to the left:

3(k-1)-(2(k-1))=0

We multiply parentheses

3k-(2(k-1))-3=0



We calculate terms in parentheses: -(2(k-1)), so:

2(k-1)

We multiply parentheses

2k-2

Back to the equation:

-(2k-2)



We get rid of parentheses

3k-2k+2-3=0

We add all the numbers together, and all the variables

k-1=0

We move all terms containing k to the left, all other terms to the right

k=1

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