4(4b-3)+6b=4(6b+4)=10

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Solution for 4(4b-3)+6b=4(6b+4)=10 equation: 



4(4b-3)+6b=4(6b+4)=10

We move all terms to the left:

4(4b-3)+6b-(4(6b+4))=0

We add all the numbers together, and all the variables

6b+4(4b-3)-(4(6b+4))=0

We multiply parentheses

6b+16b-(4(6b+4))-12=0



We calculate terms in parentheses: -(4(6b+4)), so:

4(6b+4)

We multiply parentheses

24b+16

Back to the equation:

-(24b+16)



We add all the numbers together, and all the variables

22b-(24b+16)-12=0

We get rid of parentheses

22b-24b-16-12=0

We add all the numbers together, and all the variables

-2b-28=0

We move all terms containing b to the left, all other terms to the right

-2b=28

b=28/-2

b=-14

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