3(k+11)=15(k-1)

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Solution for 3(k+11)=15(k-1) equation: 



3(k+11)=15(k-1)

We move all terms to the left:

3(k+11)-(15(k-1))=0

We multiply parentheses

3k-(15(k-1))+33=0



We calculate terms in parentheses: -(15(k-1)), so:

15(k-1)

We multiply parentheses

15k-15

Back to the equation:

-(15k-15)



We get rid of parentheses

3k-15k+15+33=0

We add all the numbers together, and all the variables

-12k+48=0

We move all terms containing k to the left, all other terms to the right

-12k=-48

k=-48/-12

k=+4

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