3(i+1)+I+2=2(2i+I)+3

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Solution for 3(i+1)+I+2=2(2i+I)+3 equation: 



3(i+1)++2=2(2i+)+3

We move all terms to the left:

3(i+1)++2-(2(2i+)+3)=0

We add all the numbers together, and all the variables

3(i+1)-(2(+2i)+3)+2+=0

We add all the numbers together, and all the variables

3(i+1)-(2(+2i)+3)=0

We multiply parentheses

3i-(2(+2i)+3)+3=0



We calculate terms in parentheses: -(2(+2i)+3), so:

2(+2i)+3

We multiply parentheses

4i+3

Back to the equation:

-(4i+3)



We get rid of parentheses

3i-4i-3+3=0

We add all the numbers together, and all the variables

-i=0

i=0/-1

i=0

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