3(h-6)=2(5-2h)-28

Solution for 3(h-6)=2(5-2h)-28 equation:

3(h-6)=2(5-2h)-28

We move all terms to the left:

3(h-6)-(2(5-2h)-28)=0

We add all the numbers together, and all the variables

3(h-6)-(2(-2h+5)-28)=0

We multiply parentheses

3h-(2(-2h+5)-28)-18=0


We calculate terms in parentheses: -(2(-2h+5)-28), so:

2(-2h+5)-28

We multiply parentheses

-4h+10-28

We add all the numbers together, and all the variables

-4h-18

Back to the equation:

-(-4h-18)


We get rid of parentheses

3h+4h+18-18=0

We add all the numbers together, and all the variables

7h=0

h=0/7

h=0