3x+2=2(x+4)-(6-x)

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Solution for 3x+2=2(x+4)-(6-x) equation: 



3x+2=2(x+4)-(6-x)

We move all terms to the left:

3x+2-(2(x+4)-(6-x))=0

We add all the numbers together, and all the variables

3x-(2(x+4)-(-1x+6))+2=0



We calculate terms in parentheses: -(2(x+4)-(-1x+6)), so:

2(x+4)-(-1x+6)

We multiply parentheses

2x-(-1x+6)+8

We get rid of parentheses

2x+1x-6+8

We add all the numbers together, and all the variables

3x+2

Back to the equation:

-(3x+2)



We get rid of parentheses

3x-3x-2+2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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