3(h+2)-(h-1)=3(h+5)

Solution for 3(h+2)-(h-1)=3(h+5) equation:

3(h+2)-(h-1)=3(h+5)

We move all terms to the left:

3(h+2)-(h-1)-(3(h+5))=0

We multiply parentheses

3h-(h-1)-(3(h+5))+6=0

We get rid of parentheses

3h-h-(3(h+5))+1+6=0


We calculate terms in parentheses: -(3(h+5)), so:

3(h+5)

We multiply parentheses

3h+15

Back to the equation:

-(3h+15)


We add all the numbers together, and all the variables

2h-(3h+15)+7=0

We get rid of parentheses

2h-3h-15+7=0

We add all the numbers together, and all the variables

-1h-8=0

We move all terms containing h to the left, all other terms to the right

-h=8

h=8/-1

h=-8