3(z-4)=7*z+2

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Solution for 3(z-4)=7*z+2 equation: 



3(z-4)=7z+2

We move all terms to the left:

3(z-4)-(7z+2)=0

We multiply parentheses

3z-(7z+2)-12=0

We get rid of parentheses

3z-7z-2-12=0

We add all the numbers together, and all the variables

-4z-14=0

We move all terms containing z to the left, all other terms to the right

-4z=14

z=14/-4

z=-3+1/2

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