3(g-7)=2+(10+g)

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Solution for 3(g-7)=2+(10+g) equation:



3(g-7)=2+(10+g)
We move all terms to the left:
3(g-7)-(2+(10+g))=0
We add all the numbers together, and all the variables
3(g-7)-(2+(g+10))=0
We multiply parentheses
3g-(2+(g+10))-21=0
We calculate terms in parentheses: -(2+(g+10)), so:
2+(g+10)
determiningTheFunctionDomain (g+10)+2
We get rid of parentheses
g+10+2
We add all the numbers together, and all the variables
g+12
Back to the equation:
-(g+12)
We get rid of parentheses
3g-g-12-21=0
We add all the numbers together, and all the variables
2g-33=0
We move all terms containing g to the left, all other terms to the right
2g=33
g=33/2
g=16+1/2

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