7-(4n-5)=9n-3(n+7)-7

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Solution for 7-(4n-5)=9n-3(n+7)-7 equation: 



7-(4n-5)=9n-3(n+7)-7

We move all terms to the left:

7-(4n-5)-(9n-3(n+7)-7)=0

We get rid of parentheses

-4n-(9n-3(n+7)-7)+5+7=0



We calculate terms in parentheses: -(9n-3(n+7)-7), so:

9n-3(n+7)-7

We multiply parentheses

9n-3n-21-7

We add all the numbers together, and all the variables

6n-28

Back to the equation:

-(6n-28)



We add all the numbers together, and all the variables

-4n-(6n-28)+12=0

We get rid of parentheses

-4n-6n+28+12=0

We add all the numbers together, and all the variables

-10n+40=0

We move all terms containing n to the left, all other terms to the right

-10n=-40

n=-40/-10

n=+4

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