3(g-5)+g=-3+4(g-3)

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Solution for 3(g-5)+g=-3+4(g-3) equation: 



3(g-5)+g=-3+4(g-3)

We move all terms to the left:

3(g-5)+g-(-3+4(g-3))=0

We add all the numbers together, and all the variables

g+3(g-5)-(-3+4(g-3))=0

We multiply parentheses

g+3g-(-3+4(g-3))-15=0



We calculate terms in parentheses: -(-3+4(g-3)), so:

-3+4(g-3)

determiningTheFunctionDomain
4(g-3)-3

We multiply parentheses

4g-12-3

We add all the numbers together, and all the variables

4g-15

Back to the equation:

-(4g-15)



We add all the numbers together, and all the variables

4g-(4g-15)-15=0

We get rid of parentheses

4g-4g+15-15=0

We add all the numbers together, and all the variables

=0

g=0/1

g=0

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