4x+12(x-3)=20

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Solution for 4x+12(x-3)=20 equation: 



4x+12(x-3)=20

We move all terms to the left:

4x+12(x-3)-(20)=0

We multiply parentheses

4x+12x-36-20=0

We add all the numbers together, and all the variables

16x-56=0

We move all terms containing x to the left, all other terms to the right

16x=56

x=56/16

x=3+1/2

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