3(f-5)=2(f+5)

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Solution for 3(f-5)=2(f+5) equation: 


Simplifying
3(f + -5) = 2(f + 5)

Reorder the terms:
3(-5 + f) = 2(f + 5)
(-5 * 3 + f * 3) = 2(f + 5)
(-15 + 3f) = 2(f + 5)

Reorder the terms:
-15 + 3f = 2(5 + f)
-15 + 3f = (5 * 2 + f * 2)
-15 + 3f = (10 + 2f)

Solving
-15 + 3f = 10 + 2f

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-2f' to each side of the equation.
-15 + 3f + -2f = 10 + 2f + -2f

Combine like terms: 3f + -2f = 1f
-15 + 1f = 10 + 2f + -2f

Combine like terms: 2f + -2f = 0
-15 + 1f = 10 + 0
-15 + 1f = 10

Add '15' to each side of the equation.
-15 + 15 + 1f = 10 + 15

Combine like terms: -15 + 15 = 0
0 + 1f = 10 + 15
1f = 10 + 15

Combine like terms: 10 + 15 = 25
1f = 25

Divide each side by '1'.
f = 25

Simplifying
f = 25

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