3x+x+(x+1)+(x+2)=72

Solution for 3x+x+(x+1)+(x+2)=72 equation:

Simplifying
3x + x + (x + 1) + (x + 2) = 72

Reorder the terms:
3x + x + (1 + x) + (x + 2) = 72

Remove parenthesis around (1 + x)
3x + x + 1 + x + (x + 2) = 72

Reorder the terms:
3x + x + 1 + x + (2 + x) = 72

Remove parenthesis around (2 + x)
3x + x + 1 + x + 2 + x = 72

Reorder the terms:
1 + 2 + 3x + x + x + x = 72

Combine like terms: 1 + 2 = 3
3 + 3x + x + x + x = 72

Combine like terms: 3x + x = 4x
3 + 4x + x + x = 72

Combine like terms: 4x + x = 5x
3 + 5x + x = 72

Combine like terms: 5x + x = 6x
3 + 6x = 72

Solving
3 + 6x = 72

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 6x = 72 + -3

Combine like terms: 3 + -3 = 0
0 + 6x = 72 + -3
6x = 72 + -3

Combine like terms: 72 + -3 = 69
6x = 69

Divide each side by '6'.
x = 11.5

Simplifying
x = 11.5