3(f-3)+5=5(f-1)

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Solution for 3(f-3)+5=5(f-1) equation: 



3(f-3)+5=5(f-1)

We move all terms to the left:

3(f-3)+5-(5(f-1))=0

We multiply parentheses

3f-(5(f-1))-9+5=0



We calculate terms in parentheses: -(5(f-1)), so:

5(f-1)

We multiply parentheses

5f-5

Back to the equation:

-(5f-5)



We add all the numbers together, and all the variables

3f-(5f-5)-4=0

We get rid of parentheses

3f-5f+5-4=0

We add all the numbers together, and all the variables

-2f+1=0

We move all terms containing f to the left, all other terms to the right

-2f=-1

f=-1/-2

f=1/2

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