3(d-8)-5=9d+19

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Solution for 3(d-8)-5=9d+19 equation: 



3(d-8)-5=9d+19

We move all terms to the left:

3(d-8)-5-(9d+19)=0

We multiply parentheses

3d-(9d+19)-24-5=0

We get rid of parentheses

3d-9d-19-24-5=0

We add all the numbers together, and all the variables

-6d-48=0

We move all terms containing d to the left, all other terms to the right

-6d=48

d=48/-6

d=-8

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