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40=3+5(x+6)
We move all terms to the left:
40-(3+5(x+6))=0
We calculate terms in parentheses: -(3+5(x+6)), so:We get rid of parentheses
3+5(x+6)
determiningTheFunctionDomain 5(x+6)+3
We multiply parentheses
5x+30+3
We add all the numbers together, and all the variables
5x+33
Back to the equation:
-(5x+33)
-5x-33+40=0
We add all the numbers together, and all the variables
-5x+7=0
We move all terms containing x to the left, all other terms to the right
-5x=-7
x=-7/-5
x=1+2/5
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