3(d-8)-5=9(d+2)+11

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Solution for 3(d-8)-5=9(d+2)+11 equation: 



3(d-8)-5=9(d+2)+11

We move all terms to the left:

3(d-8)-5-(9(d+2)+11)=0

We multiply parentheses

3d-(9(d+2)+11)-24-5=0



We calculate terms in parentheses: -(9(d+2)+11), so:

9(d+2)+11

We multiply parentheses

9d+18+11

We add all the numbers together, and all the variables

9d+29

Back to the equation:

-(9d+29)



We add all the numbers together, and all the variables

3d-(9d+29)-29=0

We get rid of parentheses

3d-9d-29-29=0

We add all the numbers together, and all the variables

-6d-58=0

We move all terms containing d to the left, all other terms to the right

-6d=58

d=58/-6

d=-9+2/3

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