4(2+2b)-4(2b-4)=24

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Solution for 4(2+2b)-4(2b-4)=24 equation: 



4(2+2b)-4(2b-4)=24

We move all terms to the left:

4(2+2b)-4(2b-4)-(24)=0

We add all the numbers together, and all the variables

4(2b+2)-4(2b-4)-24=0

We multiply parentheses

8b-8b+8+16-24=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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