3(d-5)=2(d+4)

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Solution for 3(d-5)=2(d+4) equation: 



3(d-5)=2(d+4)

We move all terms to the left:

3(d-5)-(2(d+4))=0

We multiply parentheses

3d-(2(d+4))-15=0



We calculate terms in parentheses: -(2(d+4)), so:

2(d+4)

We multiply parentheses

2d+8

Back to the equation:

-(2d+8)



We get rid of parentheses

3d-2d-8-15=0

We add all the numbers together, and all the variables

d-23=0

We move all terms containing d to the left, all other terms to the right

d=23

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