3(d+12)=4(2-d)

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Solution for 3(d+12)=4(2-d) equation: 



3(d+12)=4(2-d)

We move all terms to the left:

3(d+12)-(4(2-d))=0

We add all the numbers together, and all the variables

3(d+12)-(4(-1d+2))=0

We multiply parentheses

3d-(4(-1d+2))+36=0



We calculate terms in parentheses: -(4(-1d+2)), so:

4(-1d+2)

We multiply parentheses

-4d+8

Back to the equation:

-(-4d+8)



We get rid of parentheses

3d+4d-8+36=0

We add all the numbers together, and all the variables

7d+28=0

We move all terms containing d to the left, all other terms to the right

7d=-28

d=-28/7

d=-4

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