3x-(2x+1)=3(x+1)-3(4-2x)

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Solution for 3x-(2x+1)=3(x+1)-3(4-2x) equation: 



3x-(2x+1)=3(x+1)-3(4-2x)

We move all terms to the left:

3x-(2x+1)-(3(x+1)-3(4-2x))=0

We add all the numbers together, and all the variables

3x-(2x+1)-(3(x+1)-3(-2x+4))=0

We get rid of parentheses

3x-2x-(3(x+1)-3(-2x+4))-1=0



We calculate terms in parentheses: -(3(x+1)-3(-2x+4)), so:

3(x+1)-3(-2x+4)

We multiply parentheses

3x+6x+3-12

We add all the numbers together, and all the variables

9x-9

Back to the equation:

-(9x-9)



We add all the numbers together, and all the variables

x-(9x-9)-1=0

We get rid of parentheses

x-9x+9-1=0

We add all the numbers together, and all the variables

-8x+8=0

We move all terms containing x to the left, all other terms to the right

-8x=-8

x=-8/-8

x=1

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