3(d+1)=2(3d-1)

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Solution for 3(d+1)=2(3d-1) equation: 



3(d+1)=2(3d-1)

We move all terms to the left:

3(d+1)-(2(3d-1))=0

We multiply parentheses

3d-(2(3d-1))+3=0



We calculate terms in parentheses: -(2(3d-1)), so:

2(3d-1)

We multiply parentheses

6d-2

Back to the equation:

-(6d-2)



We get rid of parentheses

3d-6d+2+3=0

We add all the numbers together, and all the variables

-3d+5=0

We move all terms containing d to the left, all other terms to the right

-3d=-5

d=-5/-3

d=1+2/3

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