3(x-4)+1=6x-3(4+x)

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Solution for 3(x-4)+1=6x-3(4+x) equation: 



3(x-4)+1=6x-3(4+x)

We move all terms to the left:

3(x-4)+1-(6x-3(4+x))=0

We add all the numbers together, and all the variables

3(x-4)-(6x-3(x+4))+1=0

We multiply parentheses

3x-(6x-3(x+4))-12+1=0



We calculate terms in parentheses: -(6x-3(x+4)), so:

6x-3(x+4)

We multiply parentheses

6x-3x-12

We add all the numbers together, and all the variables

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

3x-(3x-12)-11=0

We get rid of parentheses

3x-3x+12-11=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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