3(c-7)=5(9-c)

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Solution for 3(c-7)=5(9-c) equation: 



3(c-7)=5(9-c)

We move all terms to the left:

3(c-7)-(5(9-c))=0

We add all the numbers together, and all the variables

3(c-7)-(5(-1c+9))=0

We multiply parentheses

3c-(5(-1c+9))-21=0



We calculate terms in parentheses: -(5(-1c+9)), so:

5(-1c+9)

We multiply parentheses

-5c+45

Back to the equation:

-(-5c+45)



We get rid of parentheses

3c+5c-45-21=0

We add all the numbers together, and all the variables

8c-66=0

We move all terms containing c to the left, all other terms to the right

8c=66

c=66/8

c=8+1/4

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